What is the perimeter of Jan's property that measures 75 feet wide by 50 feet deep?

What is the perimeter of Jan's property that measures 75 feet wide by 50 feet deep?

• A. 125 linear feet
• B. 175 linear feet
• C. 250 linear feet
• D. 275 linear feet

Answer: (C)

To find the perimeter of a rectangular property, the formula used is the sum of all sides, which can be expressed as: Perimeter = 2(Width + Depth) In this case, Jan’s property is 75 feet wide and 50 feet deep. Plugging in the values: Perimeter = 2(75 feet + 50 feet) = 2(125 feet) = 250 feet This calculation shows that Jan's property has a perimeter of 250 linear feet, which corresponds to the correct answer choice. Understanding the perimeter calculation process is crucial in real estate to accurately represent the dimensions and characteristics of a property.

To find the perimeter of a rectangular property, the formula used is the sum of all sides, which can be expressed as:

Perimeter = 2(Width + Depth)

In this case, Jan’s property is 75 feet wide and 50 feet deep.

Plugging in the values:

Perimeter = 2(75 feet + 50 feet)

= 2(125 feet)

= 250 feet

This calculation shows that Jan's property has a perimeter of 250 linear feet, which corresponds to the correct answer choice. Understanding the perimeter calculation process is crucial in real estate to accurately represent the dimensions and characteristics of a property.